Three particles of mass 20 g, 30 g and 40 g are initially moving along the positive direction of the three coordinate axes x, y and z respectively with the same velocity of 20 cm/s. If due to their mutual interaction, the first particle comes to rest, the second acquires a velocity 
. What is the velocity (in cm/s) of the third particle?
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
P 1 =20 × 20 
P 3 = 40 × 20 
P 2 = 30 × 20 
P i = P 1 + P 2 + P 3 = P f
⇒ 400i + 600 
+ 800 
= 30 (10i + 20 
) + 40v
Get v = 
= 2.5 
+ 15 
+ 5 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A particle of mass m is moving along the x-axis with speed v when it collides with a particle of ma…
The diagram shows the velocity - time graph for two masses R and S that collided head on elasticall…
A stationary body explodes into two fragments of masses m 1 and m 2 . If momentum of one fragment i…
A train of mass M = π kg is moving on a circular track of radius ' R ' with constant speed V = 2m/s…
A man of mass 60 kg start falling from building of height 80 m with a bag of 2 kg in his hand. Afte…
A railway flat car has an artillery gun installed on it and contains shells for firing The combined…